Commit 01b27247 authored by Claude Meny's avatar Claude Meny

Update textbook.fr.md

parent a25475ca
Pipeline #17078 canceled with stage
......@@ -194,11 +194,11 @@ Si de plus la distribution de courants $`\overrightarrow{j}`$ est invariante par
\end{array}\right\}}`$
$`\mathbf{\Longrightarrow \overrightarrow{j} = \overrightarrow{j} (\beta)\Longrightarrow \overrightarrow{B}=\overrightarrow{B}\,(\beta)}`$**
$`\begin{align}
\begin{array}
\overrightarrow{j}\,(\xcancel{\alpha},\beta, \gamma) =\overrightarrow{j}\,(\beta,\gamma) \\
\overrightarrow{j}\,(\alpha,\beta, \xcancel{\gamma}) =\overrightarrow{j}\,(\alpha,\beta)
\end{array}\right\}&\Longrightarrow \overrightarrow{j} = \overrightarrow{j} (\beta)\Longrightarrow \overrightarrow{B}}\\
$`\begin{align}\left.
\begin{align}
&\overrightarrow{j}\,(\xcancel{\alpha},\beta, \gamma) =\overrightarrow{j}\,(\beta,\gamma) \\
&\overrightarrow{j}\,(\alpha,\beta, \xcancel{\gamma}) =\overrightarrow{j}\,(\alpha,\beta)
\end{align}\right\}&\Longrightarrow \overrightarrow{j} = \overrightarrow{j} (\beta)\Longrightarrow \overrightarrow{B}}\\
&\Longrightarrow \overrightarrow{B}=\overrightarrow{B}\,(\beta)
\end{align}`$
......
Markdown is supported
0% or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment