Update cheatsheet.fr.md

12.temporary_ins/10.electrostatics-vacuum/20.causes-stationary-electric-field/20.overview/cheatsheet.fr.md

@@ -784,11 +784,8 @@ figure à faire
     \times
     \int_{\rho=0}^{R} \rho\,(\rho^2+z_M^2)^{\,-3/2}\,d\rho`$    
     <br>
-    $`\displaystyle \hspace{1cm} =  
-    \dfrac{\dens^{2D}\,z}{2\epsilon_0}
-    \int_{\rho = 0}^R
-    - \Big(\underbrace{-\dfrac{1}{2}_{n+1}\Big)}\cdot
-    \underbrace{2\rho}_{u^{\,'}}\,\underbrace{(\rho^2+z^2)^{-\,3/2}}_{u^n}\,d\rho`$   
+    $`\displaystyle\hspace{1cm}=\dfrac{\dens^{2D}\,z}{2\epsilon_0}`$   
+    $`\int_{\rho = 0}^R - \Big(\underbrace{-\dfrac{1}{2}_{n+1}\Big)}\cdot\underbrace{2\rho}_{u^{\,'}}\,\underbrace{(\rho^2+z^2)^{-\,3/2}}_{u^n}\,d\rho`$   
     <br>
     $`\displaystyle \hspace{1cm} =  - \dfrac{\dens^{2D}\,z}{2\epsilon_0} \big[(\rho^2+z^2)^{-\,1/2}\big]_0^R`$  
     <br>