Update cheatsheet.fr.md

12.temporary_ins/80.energie-transformations-applications-impacts/20.n2/50.energy-mix/40.TD-hydroelectricity/60.parallel-2/cheatsheet.fr.md

@@ -203,8 +203,8 @@ $`\hspace{1,6cm}=(4,1\times 10^4)\times (3,1 \times 10^7)\;J.an^{-1}`$
 
 $`\hspace{1,6cm} = 12,7\times 10^{11}\,J.an^{-1}\times\mathcal{F}_{J\rightarrow kWh}`$
 
-$`\hspace{1,6cm}\begin{align}= (12,7\times 10^{11}\;&J.an^{-1})\\
-&\times (2,8\times 10^{-7}\;kWh.J^{-1})\end{align}`$
+$`\hspace{1,6cm}\begin{align}= (12,7\times &10^{11}\;J.an^{-1})\\
+&\;\times (2,8\times 10^{-7}\;kWh.J^{-1})\end{align}`$
 
 **$`\mathbf{\hspace{1,6cm}\simeq 3,6\times 10^{5}\;kWh.an^{-1}}`$**