Commit 3906ce40 authored by Claude Meny's avatar Claude Meny

Update cheatsheet.fr.md

parent 4ac5bda2
Pipeline #15658 canceled with stage
......@@ -628,11 +628,23 @@ $`\quad\boldsymbol{\mathbf{=\color{brown}{2\,A\cdot cos\Big(\dfrac{\varphi_1-\va
$`\color{blue}{\scriptsize{ \quad\text{En posant } p=a+b \text{ et } q=a-b\;,}}`$
$`\color{blue}{\scriptsize{\quad \text{nous obtenons } a = (p+q)\,/\,2 \text{ et } b = (p-q)\,/\,2.}}`$
$`\color{blue}{\scriptsize{ \quad\text{Nous retrouvons ainsi }}}`$
$`\color{blue}{\scriptsize{ \quad\quad cos(p) + cos(q) = 2\,cos\Big(\dfrac{p+q}{2}\Big)\,cos\Big(\dfrac{p-q}{2}\Big)}}`$
$`\color{blue}{\scriptsize{ \quad\quad cos(p) + cos(q) = 2\,cos\Big(\dfrac{p+q}{2}\Big)\,cos\Big(\dfrac{p-q}{2}\Big)}}`$
<br>
$`\quad \begin{align}=A\;\Big[\,&c\alpha\cdot 2\,cos\Big(\dfrac{\varphi_1+\varphi_2}{2}\Big)\,cos\Big(\dfrac{\varphi_1-\varphi_2}{2}\Big)\\
&- s\alpha\cdot 2\,sin\Big(\dfrac{\varphi_1+\varphi_2}{2}\Big)\,sin\Big(\dfrac{\varphi_1-\varphi_2}{2}\Big)\end{align}`$
$`\color{blue}{\scriptsize{ \quad\text{De même nous retrouverions }}}`$
$`\color{blue}{\scriptsize{ \quad\quad sin(p) + sin(q) = 2\,sin\Big(\dfrac{p+q}{2}\Big)\,cos\Big(\dfrac{p-q}{2}\Big)}}`$
<br>
$`\quad \begin{align}=A\;\Big[\,&c\alpha\cdot 2\,c\Big(\dfrac{\varphi_1+\varphi_2}{2}\Big)\,c\Big(\dfrac{\varphi_1-\varphi_2}{2}\Big)\\
&- s\alpha\cdot 2\,s\Big(\dfrac{\varphi_1+\varphi_2}{2}\Big)\,c\Big(\dfrac{\varphi_1-\varphi_2}{2}\Big)\end{align}`$
<br>
$`\quad \begin{align}=2\,A\;&c\Big(\dfrac{\varphi_1-\varphi_2}{2}\Big)\\
&\times \Big[\,c\alpha\,c\Big(\dfrac{\varphi_1+\varphi_2}{2}\Big)-s\alpha\,s\Big(\dfrac{\varphi_1+\varphi_2}{2}\Big)\,\Big]\end{align)`$
]
\Big[\,&c\alpha\cdot 2\,cos\Big(\dfrac{\varphi_1+\varphi_2}{2}\Big)\,cos\Big(\dfrac{\varphi_1-\varphi_2}{2}\Big)\\
&- s\alpha\cdot 2\,sin\Big(\dfrac{\varphi_1+\varphi_2}{2}\Big)\,cos\Big(\dfrac{\varphi_1-\varphi_2}{2}\Big)\end{align}`$
......
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