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M3P2
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6b2ed0d8
Commit
6b2ed0d8
authored
May 20, 2023
by
Claude Meny
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Update cheatsheet.fr.md
parent
ff2b0b9b
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#16015
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cheatsheet.fr.md
...electromagnetic-waves-vacuum/20.overview/cheatsheet.fr.md
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12.temporary_ins/90.electromagnetism-in-vacuum/20.electromagnetic-waves-vacuum/20.overview/cheatsheet.fr.md
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6b2ed0d8
...
...
@@ -218,14 +218,14 @@ puis d'une onde plane progressive monochromatique (OPPM).
\mu_0\,\overrightarrow{j}+\overbrace{\mu_0\epsilon_0}^{=\;\dfrac{1}{c^2}}\,\dfrac{\partial \overrightarrow{E}}{\partial t}}_{\color{blue}{\text{th. de Maxwell-Faraday}}}
=\dfrac{1}{c^2}\,\dfrac{\partial \overrightarrow{E}}{\partial t}\\
\\
&\overrightarrow{B}\;uniforme\
\
&
dans\;tout\;plan\;\perp\overrightarrow{e_z}\end{align}\right\}`
$
&\overrightarrow{B}\;uniforme\
;
dans\;tout\;plan\;\perp\overrightarrow{e_z}\end{align}\right\}`
$
<br>
$
`\Longrightarrow\left\{
\begin{align}
&\dfrac{\partial B_z}{\partial y}-\dfrac{\partial B_y}{\partial z}=\dfrac{1}{c^2}\;\dfrac{\partial E_x}{\partial t}\\
&\dfrac{\partial B_x}{\partial z}-\dfrac{\partial B_z}{\partial x}=\dfrac{1}{c^2}\;\dfrac{\partial E_y}{\partial t}
}
\\
&\dfrac{\partial B_y}{\partial x}-\dfrac{\partial B_x}{\partial y}=
=
\dfrac{1}{c^2}\;\dfrac{\partial E_z}{\partial t}\\
&\dfrac{\partial B_x}{\partial z}-\dfrac{\partial B_z}{\partial x}=\dfrac{1}{c^2}\;\dfrac{\partial E_y}{\partial t}\\
&\dfrac{\partial B_y}{\partial x}-\dfrac{\partial B_x}{\partial y}=\dfrac{1}{c^2}\;\dfrac{\partial E_z}{\partial t}\\
\\
&\dfrac{\partial B_z}{\partial y}=\dfrac{\partial B_y}{\partial z}=\dfrac{\partial B_x}{\partial z}=\dfrac{\partial B_z}{\partial x}\\
&\quad =\dfrac{\partial B_y}{\partial x}=\dfrac{\partial B_x}{\partial y}=0
...
...
@@ -233,11 +233,11 @@ puis d'une onde plane progressive monochromatique (OPPM).
<br>
*
$
`\Longrightarrow\left\{
\begin{align}
&-\dfrac{\partial B_
z}{\partial x}=\dfrac{1}{c^2}\;\dfrac{\partial E_y
}{\partial t}\\
&-\dfrac{\partial B_
y}{\partial z}=\dfrac{1}{c^2}\;\dfrac{\partial E_x
}{\partial t}\\
\\
&\dfrac{\partial B_
y}{\partial x}=\dfrac{1}{c^2}\;\dfrac{\partial E_z
}{\partial t}\\
&\dfrac{\partial B_
x}{\partial z}=\dfrac{1}{c^2}\;\dfrac{\partial E_y
}{\partial t}\\
\\
&\dfrac{\partial
B
_z}{\partial t}=0
&\dfrac{\partial
E
_z}{\partial t}=0
\end{align}\right.`
$
*
...
...
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