Commit 86dafd36 authored by Claude Meny's avatar Claude Meny

Update cheatsheet.fr.md

parent 51af2340
Pipeline #12789 canceled with stage
...@@ -191,16 +191,20 @@ $`\iint_S \overrightarrow{rot} \,\overrightarrow{E}\cdot\overrightarrow{dS} = -\ ...@@ -191,16 +191,20 @@ $`\iint_S \overrightarrow{rot} \,\overrightarrow{E}\cdot\overrightarrow{dS} = -\
$`\Longrightarrow \iint_S \overrightarrow{rot} \,\overrightarrow{B}\cdot\overrightarrow{dS} = \iint_S\Big(\mu_0\;\overrightarrow{j} + \mu_0 \epsilon_0 \;\dfrac{\partial \overrightarrow{E}}{\partial t}\Big)\cdot\overrightarrow{dS}`$ $`\Longrightarrow \iint_S \overrightarrow{rot} \,\overrightarrow{B}\cdot\overrightarrow{dS} = \iint_S\Big(\mu_0\;\overrightarrow{j} + \mu_0 \epsilon_0 \;\dfrac{\partial \overrightarrow{E}}{\partial t}\Big)\cdot\overrightarrow{dS}`$
à terminer * $`\left.\begin{array}{l}
\iint_S \overrightarrow{rot} \,\overrightarrow{B}\cdot\overrightarrow{dS} = \iint_S\Big(\mu_0\;\overrightarrow{j} + \mu_0 \epsilon_0 \;\dfrac{\partial \overrightarrow{E}}{\partial t}\Big)\cdot\overrightarrow{dS} \\
\text{Newton : espace et temps indépendants}
\end{array}\right\}
\Longrightarrow`$
$`\iint_S \overrightarrow{rot} \,\overrightarrow{B}\cdot\overrightarrow{dS} = -\dfrac{d}{dt}\Big(\iint_S\overrightarrow{B}\cdot\overrightarrow{dS}\Big)`$
<!----------------
* $`\left.\begin{array}{l} * $`\left.\begin{array}{l}
\iint_S \overrightarrow{rot} \,\overrightarrow{B}\cdot\overrightarrow{dS} = \iint_S\Big(\mu_0\;\overrightarrow{j} + \mu_0 \epsilon_0 \;\dfrac{\partial \overrightarrow{E}}{\partial t}\Big)\cdot\overrightarrow{dS} \\ \iint_S \overrightarrow{rot} \,\overrightarrow{B}\cdot\overrightarrow{dS} = \iint_S\Big(\mu_0\;\overrightarrow{j} + \mu_0 \epsilon_0 \;\dfrac{\partial \overrightarrow{E}}{\partial t}\Big)\cdot\overrightarrow{dS} \\
\text{Newton : espace et temps indépendants} \text{Newton : espace et temps indépendants}
\end{array}\right\} \end{array}\right\}
\Longrightarrow`$ \Longrightarrow`$
$`\iint_S \overrightarrow{rot} \,\overrightarrow{B}\cdot\overrightarrow{dS} = \mu_0\iint_S \overrightarrow{j}\cdot\overrightarrow{dS} $`\iint_S \overrightarrow{rot} \,\overrightarrow{B}\cdot\overrightarrow{dS} = \mu_0\iint_S \overrightarrow{j}\cdot\overrightarrow{dS} +
\mu_0 \epsilon_0\dfrac{d}{dt}\iint_S\overrightarrow{E}\cdot\overrightarrow{dS}`$ \mu_0 \epsilon_0\dfrac{d}{dt}\iint_S\overrightarrow{E}\cdot\overrightarrow{dS}`$
......
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