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M3P2
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a7fc6700
Commit
a7fc6700
authored
Feb 09, 2025
by
Claude Meny
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Update cheatsheet.fr.md
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12.temporary_ins/80.energie-transformations-applications-impacts/20.n2/50.energy-mix/40.TD-hydroelectricity/60.parallel-2/cheatsheet.fr.md
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a7fc6700
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@@ -212,14 +212,38 @@ _(source : particuliers.engie.fr)_.
...
@@ -212,14 +212,38 @@ _(source : particuliers.engie.fr)_.
<br>
<br>
*$`\mathbf{\text{nombre}_{\;foyers}\simeq\dfrac{36\times 10^4}{2,0\times 10^4}\simeq 18\;\text{foyers}}`$*
*$`\mathbf{\text{nombre}_{\;foyers}\simeq\dfrac{36\times 10^4}{2,0\times 10^4}\simeq 18\;\text{foyers}}`$*
(erreur à corriger ci-dessus)
)
</details>
</details>
<br>
------
------
##### 3. **Facteur de charge** et *type d'utilisation*<br><br>a) Calculer le facteur de charge de cette micro-centrale
<details
markdown=
1
><summary>
Solution
</summary>
*
*Facteur de conversion*
énergétique depuis le
*Joule vers le kWh*
<br>
*$`\boldsymbol{\mathbf{\mathcal{F}_{J\rightarrow kWh}}}`$*
$
`=\dfrac{1\,kWh}{3,6\times 10^6\,J}
=\dfrac{1}{3,6\times 10^6}\;kWh.J^{-1}`
$
*$`\hspace{1,6cm}\mathbf{\simeq 2,8\times 10^{-7}\;kWh.J^{-1}}`$*
*
**Facteur de charge**
<br>
**$`\mathbf{F_{charge}=\dfrac{E_{\Delta t}}{P_c \times\Delta t}=\dfrac{P_{moy}(\Delta t)}{P_c}}`$**
$
`\hspace{1,6cm}=\dfrac{E_{\,1\,an}^{\,elec}}{P_c \times\text{nb s/an}}`
$
$
`\hspace{1,6cm}=\dfrac{3,6\times 10^{5}}{90\underbrace{\times 365\times 24}_{\text{nombre d' h. par an}}}`
$
**$`\hspace{1,6cm}=0,45\mathbf{=45\%}`$**
</details>
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