Update cheatsheet.fr.md

12.temporary_ins/20.magnetostatics-vacuum/40.ampere-theorem-applications/30.cylindrical-current-distributions/20.solenoidal-current/10.ampere-integral/20.overview/cheatsheet.fr.md

@@ -235,22 +235,11 @@ $`\Longrightarrow\quad\overrightarrow{dl} \cdot \overrightarrow{B}=0`$
   déterminer totalement le sens de parcours sur tout $`\mathbf{\Gamma_A}`$. Choisissons par exemple la branche DA qui contient le point $`M`$ :
 
 * Si **$`\mathbf{\overrightarrow{dl_{DA}}=+\,dz\,\overrightarrow{e_z}}`$** :
- <br>
- **$`\mathbf{\oint_{\Gamma_A}\overrightarrow{B}\cdot\overrightarrow{dl}}`$**   
- <br>
- $`\begin{align}\quad\quad=&\int_D^A \overrightarrow{B}\cdot\,dz\overrightarrow{e_z} + \int_A^B \underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}}_
-    {\color{blue}{=\,0}}\\
-             &\int_B^C \overrightarrow{B}\cdot\,dz\overrightarrow{e_z} + \int_C^D \underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}}_
-    {\color{blue}{=\,0}}
-    \end{align}`$
-
-* **$`\mathbf{\oint_{\Gamma_A}\overrightarrow{B}\cdot\overrightarrow{dl}}`$**
-     $`\begin{align}=&\int_D^A \overrightarrow{B}\cdot\,dz\overrightarrow{e_z} + \int_A^B \underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}}_
-    {\color{blue}{=\,0}}\\
-             &\int_B^C \overrightarrow{B}\cdot\,dz\overrightarrow{e_z} + \int_C^D \underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}}_
-    {\color{blue}{=\,0}}
-    \end{align}`$
-
+ <br><br>
+ **$`\mathbf{\oint_{\Gamma_A}\overrightarrow{B}\cdot\overrightarrow{dl}}`$** $`\,=\int_D^A \overrightarrow{B}\cdot\,dz\overrightarrow{e_z} + \int_A^B \underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}}_
+    {\color{blue}{=\,0}}`$     
+ $`\quad\quad\quad\quad +\int_B^C \overrightarrow{B}\cdot\,dz\overrightarrow{e_z} + \int_C^D \underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}}_
+    {\color{blue}{=\,0}}`$