Commit ba732a5a authored by Claude Meny's avatar Claude Meny

Update cheatsheet.fr.md

parent af6f98d4
Pipeline #17001 canceled with stage
......@@ -289,18 +289,19 @@ $`\mathbf{\forall M \in \mathscr{E}\; , \; B_{\rho}=B_z=0}`$
* $`\Longrightarrow`$ l'expression du *rotarionnel de $`\overrightarrow{B}`$ se simplifie* en tout point de l'espace :
**$`\mathbf{\overrightarrow{rot}\,\overrightarrow{B}}`$**
$`\begin{align}
&\boldsymbol{\mathbf{\;=\left(\dfrac{1}{\rho}\,\dfrac{\partial B_z}{\partial\varphi}\;-\;\dfrac{\partial B_{\varphi}}{\partial z}\right)\,\overrightarrow{e_{\rho}}}}\\
$`\require{\cancel}\begin{align}
\color{brown}{\mathbf{\overrightarrow{rot}\,\overrightarrow{B}}}
&\;=\left(\dfrac{1}{\rho}\,\dfrac{\partial B_z}{\partial\varphi}\;-\;\dfrac{\partial B_{\varphi}}{\partial z}\right)\,\overrightarrow{e_{\rho}}\\
\\
&\boldsymbol{\mathbf{\quad\; +\left(\dfrac{\partial B_{\rho}}{\partial z}\;-\;\dfrac{\partial B_z}{\partial \rho}\right)\,\overrightarrow{e_{\varphi}}}}\\
&\quad\; +\left(\dfrac{\partial B_{\rho}}{\partial z}\;-\;\dfrac{\partial B_z}{\partial \rho}\right)\,\overrightarrow{e_{\varphi}}\\
\\
&\boldsymbol{\mathbf{\quad\; +
&\quad\; +
\,\dfrac{1}{\rho}\,\left(\dfrac{\partial (\,\rho\,B_{\varphi})}{\partial \rho}\;-\;\dfrac{\partial B_{\rho}}{\partial \varphi}\right)
\,\overrightarrow{e_z}}}
\,\overrightarrow{e_z}
\end{align}`$**
$`\require{\cancel}=\dfrac{1}{\rho}\cdot\dfrac{\partial\left(\rho\,E_{\rho}\right)}{\partial\,\rho}
$`=\dfrac{1}{\rho}\cdot\dfrac{\partial\left(\rho\,E_{\rho}\right)}{\partial\,\rho}
+\xcancel{\dfrac{1}{\rho}\cdot\dfrac{\partial\,E_{\varphi}}{\partial\,\varphi}}
+\xcancel{\dfrac{\partial\,E_z}{\partial\,z}}`$
**$`\mathbf{\quad\quad=\dfrac{1}{\rho}\cdot\dfrac{\partial\left(\rho\,E_{\rho}\right)}{\partial\,\rho}}`$**
......
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