Commit cd1b6982 authored by Claude Meny's avatar Claude Meny

Update cheatsheet.fr.md

parent 6bceebf1
Pipeline #16224 canceled with stage
...@@ -238,13 +238,13 @@ $`\Longrightarrow\quad\overrightarrow{dl} \cdot \overrightarrow{B}=0`$ ...@@ -238,13 +238,13 @@ $`\Longrightarrow\quad\overrightarrow{dl} \cdot \overrightarrow{B}=0`$
<br><br> <br><br>
**$`\mathbf{\oint_{\Gamma_A}\overrightarrow{B}\cdot\overrightarrow{dl}}`$** **$`\mathbf{\oint_{\Gamma_A}\overrightarrow{B}\cdot\overrightarrow{dl}}`$**
$`\displaystyle\,=\int_{DA} \overrightarrow{B}(\rho_{DA})\cdot\overrightarrow{dl}_{DA} + \int_{AB} \underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}_{AB}}_{\color{blue}{\quad\;=\,0\\car\,\vec{B}\,\perp\,\vec{dl}_{AB}}}`$ $`\displaystyle\,=\int_{DA} \overrightarrow{B}(\rho_{DA})\cdot\overrightarrow{dl}_{DA} + \int_{AB} \underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}_{AB}}_{\color{blue}{\quad\;=\,0\\car\,\vec{B}\,\perp\,\vec{dl}_{AB}}}`$
$`\displaystyle\quad\quad\quad\quad +\int_{BC} \underbrace{\overrightarrow{B}(\rho_{BC})}_{\color{blue}{=\,0}}\cdot\overrightarrow{dl}_{BC} + \int_{CD}\underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}_{CD}}_{\color{blue}{\quad\;=\,0\\car\,\vec{B}\,\perp\,\vec{dl}_{CD}}`$ $`\displaystyle\quad\quad\quad\quad +\int_{BC} \underbrace{\overrightarrow{B}(\rho_{BC})}_{\color{blue}{=\,0}}\cdot\overrightarrow{dl}_{BC} + \int_{CD}\underbrace{\overrightarrow{B}\cdot\overrightarrow{dl}_{CD}}_{\color{blue}{\quad\;=\,0\\car\,\vec{B}\,\perp\,\vec{dl}_{CD}}}`$
<br> <br>
$`\color{blue}{\scriptsize{\text{le sens de parcours est indiqué par l'ordre des bornes d'intégration}}}`$ $`\color{blue}{\scriptsize{\text{le sens de parcours est indiqué par l'ordre des bornes d'intégration}}}`$
<br> <br>
$`\displaystyle\quad\quad\quad\quad = \int_D^A \underbrace{\overrightarrow{B}(\rho_{BC})}\cdot\,dz\,\overrightarrow{e_z}`$ $`\displaystyle\quad\quad\quad\quad = \int_D^A \underbrace{\overrightarrow{B}(\rho_{DA})}\cdot\,dz\,\overrightarrow{e_z}`$
<br> <br>
$`\displaystyle\quad\quad\quad\quad = \int_{z=z_0}^{z=z_0+h} \underbrace{B_z(\rho_{BC})}\,dz`$ $`\displaystyle\quad\quad\quad\quad = \int_{z=z_0}^{z=z_0+h} \underbrace{B_z(\rho_{DA})}\,dz`$
<br> <br>
$`\displaystyle\quad\quad\quad\quad = \Big[ B_z(\rho_{DA})\times z\Big]_{z_0}^{z_0+h}`$ $`\displaystyle\quad\quad\quad\quad = \Big[ B_z(\rho_{DA})\times z\Big]_{z_0}^{z_0+h}`$
<br> <br>
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