Update textbook.en.md

10.brainstorming-innovative-courses/intercambio-curso-electromagnetismo/textbook.en.md

@@ -696,11 +696,11 @@ $`\displaystyle\oiint_S\vec{B}\cdot\vec{dS}=0`$
 $`\displaystyle\iiint_{\tau} div\vec{E} \cdot d\tau= \displaystyle\iiint_{\tau} \dfrac{\rho}{\epsilon_0} \cdot d\tau = \dfrac{1}{\epsilon_0} \cdot \iiint_{\tau} \rho \cdot d\tau = \dfrac{Q_{int}}{\epsilon_0} `$
 
 
-$`\displaystyle\iiint_{\tau} \overrightarrow{rot}\,\overrightarrow{E}\cdot d\tau = - \displaystyle\iint_{\S \leftrightarrow \tau} \overrightarrow{B}}\cdot dS`$
+$`\displaystyle\iint_S} \overrightarrow{rot}\,\overrightarrow{E}\cdot dS = -\displaystyle\iint_{S \leftrightarrow \tau} \overrightarrow{B}}\cdot dS`$
 
 Mecánica newtoniana : espacio y el tiempo son desacoplados $ \ Longrightarrow` $ orden de integración / derivación entre variables de espacio y tiempo no importa.
 
-$`\displaystyle\iiint_{\tau} \overrightarrow{rot}\,\overrightarrow{E}\cdot d\tau = - \dfrac{\partial}{\partial t} \left( \displaystyle\iiint_{\tau} \dfrac{\partial \vec{B}}{\partial t}\cdot d\tau`$
+$`\displaystyle\iint_S}  \overrightarrow{rot}\,\overrightarrow{E}\cdot dS = - \dfrac{\partial}{\partial t} \left( \displaystyle\iint_S \overrightarrow{B}\cdot dS`$
 
 Ostrogradsky’s theorem : for all vectorial field $`\vec{X}`$,